A line drawn from a planet to the Sun will sweep over equal areas in equal amounts of time
 |
[NMSU, N. Vogt] |
The square (second power) of the period of a planet is
directly proportional to the cube (third power) of its orbital radius
(P2 = R3). This is because the closer a planet lies to
the Sun, the faster it must spin to resist the gravitational attraction (and
to avoid falling into the Sun).
Planet |
Period P |
Orbital Radius R |
P2 / R3 |
|
(years) |
(A.U.) |
(yr2 / A.U.3) |
Mercury |
0.241 |
0.39 |
0.98 |
Venus |
0.615 |
0.72 |
1.01 |
Earth |
1.00 |
1.00 |
1.00 |
Mars |
1.88 |
1.52 |
1.01 |
Jupiter |
11.8 |
5.20 |
0.99 |
Saturn |
29.5 |
9.54 |
1.00 |
Uranus |
84.0 |
19.18 |
1.00 |
Neptune |
165 |
30.06 |
1.00 |
Pluto |
248 |
39.44 |
1.00 |
When we plot the planetary radii against their periods, we see that they fall
on a straight line. If we know how far a planet lies from the Sun, we can
determine the length of its year. Likewise, if we know how long it takes
for a planet to orbit the Sun, we can determine its orbital radius.
 |
[NMSU, N. Vogt] |