For one person, she may be born on any day of the year and so P1 = 365 / 365 = 1.
For a second person, he may be born on all but one day of the year and so P2 = 364 / 365.
For a third person, she may be born on all but two days of year and so P3 = 363 / 365.
For an nth person, Pn = (365 - n + 1) / 365.
The probability P of different birthdays for all n people is the product of the individual probabilities.
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The probability P(n) that at least two of the n people were born on the same day of the year is simply the conjugate of P.
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We can easily calculate a few cases, to find the region around P(n) = 50%.
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Remember that sometimes it is much easier to calculate the conjugate of the case that you want than to consider every case which meets your criteria.