#!/bin/sh
# die - a script to kill most unruly programs most of the times.  See disclaimers
# RTH 07/29/04 - First try. Works 90% of the time
# RTH 09/28/07 - Fixed many annoyances.  Coding while lightly buzzed, caveat emptor
#  Disclaimers:
#   - Anything other than a y/n or Y/N will exit without error.  Need another case statement
#   - It doesn't deal with multiple instances of a given program, and ignores defunct/zombie
#     processes.  Should just be a loop/array setup though, easy to implement
# General notes:
#   grep -v = find all things NOT patching the "pattern"
#   `execute everything in this quotes first`
#   Pipes are your friends!
#   exit 1 bails, sort of like a return -1 in C
# Error checking, bail if no arguments given (otherwise would kill our terminal!)
if test $# = 0
then
  echo "You didn't tell me what to kill!"
  exit 1
fi
# This next bit removes all references of $1 in our script - awk and grep and even /bin/sh will show up
# in the list without filtering them out like this.  You could also do this in sed, or just about any other
# UNIX filter old skool style.  This is all for safety sake, strictly speaking the first instance showing up
# should be the one with the lowest PID and the one started earliest on the system.  But this uses more
# functions and stuff :)
# Nifty trick - note how you can jump in and out of the awk environment to get at my input variable $1
pidder=`ps -ef | grep $USER | grep $1 | awk '{if ($8~'$1') {print $0} }' | \\
        grep -v "/bin/sh" | grep -v "awk" | grep -v "grep" | grep -v "defunct"`
if `echo $pidder | grep -qv $1`
then
  echo "Sorry, nothing called \"$1\" was found running.  Perhaps another name?";
  exit 1
fi
echo "Killing:  $pidder"
read -p "Really do it? (y/n) " answer
ans=`echo $answer | tr [A-Z] [a-z]`
case $ans in
  \y) kill -9 `echo $pidder | awk '{print $2}'` ;;
  \n) exit 1 ;;
esac